ส่งการบ้าน Week03 ฟังก์ชั่น value กับ values

week03/Chapter 03 Numerics and Error Analysis.ipynb

@@ -235,6 +235,7 @@
    "cell_type": "code",
    "execution_count": 15,
    "metadata": {
+    "collapsed": true,
     "slideshow": {
      "slide_type": "skip"
     }
@@ -289,6 +290,7 @@
    "cell_type": "code",
    "execution_count": 26,
    "metadata": {
+    "collapsed": true,
     "slideshow": {
      "slide_type": "skip"
     }
@@ -336,6 +338,82 @@
     "$0.1 \\times 0.1 = 0.01 \\approx 0.0$ \n"
    ]
   },
+  {
+   "cell_type": "code",
+   "execution_count": 6,
+   "metadata": {},
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "คำตอบ : 1.5\n"
+     ]
+    },
+    {
+     "data": {
+      "text/plain": [
+       "1.5"
+      ]
+     },
+     "execution_count": 6,
+     "metadata": {},
+     "output_type": "execute_result"
+    }
+   ],
+   "source": [
+    "#0 0000 000\n",
+    "#0 0011 000 => 3\n",
+    "#0 0001 100 => 1.5\n",
+    "v=[0,0,0,0,1,1,0,0]\n",
+    "sign = -1 if v[0] == 1 else 1  #if ง่ายๆ\n",
+    "value = v[1]*2**3\n",
+    "value += v[2]*2**2\n",
+    "value += v[3]*2**1\n",
+    "value += v[4]*2**0\n",
+    "\n",
+    "value += v[5]*2**-1\n",
+    "value += v[6]*2**-2\n",
+    "value += v[7]*2**-3\n",
+    "\n",
+    "print('คำตอบ :',sign*value)\n",
+    "\n",
+    "[ (i,4-i) for i in range(1,8)]\n",
+    "[ v[i]*2**(4-i) for i in range(1,8)]\n",
+    "sum([ v[i]*2**(4-i) for i in range(1,8)])"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 10,
+   "metadata": {
+    "collapsed": true
+   },
+   "outputs": [],
+   "source": [
+    "def value(v):     #ออกสอบนาจ๊าาาาาาา      เทียบ\n",
+    "    sign = -1 if v[0] == 1 else 1  #if ง่ายๆ\n",
+    "    return sign*sum([ v[i]*2**(4-i) for i in range(1,8)])"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": null,
+   "metadata": {},
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "-2.375\n"
+     ]
+    }
+   ],
+   "source": [
+    "v = [1,0,0,1,0,0,1,1];\n",
+    "print(value(v))\n"
+   ]
+  },
   {
    "cell_type": "markdown",
    "metadata": {
@@ -472,7 +550,7 @@
    "name": "python",
    "nbconvert_exporter": "python",
    "pygments_lexer": "ipython3",
-   "version": "3.5.2"
+   "version": "3.6.3"
   }
  },
  "nbformat": 4,

week03/assignment.py

+def value(v,p=4,n=3):
+    """รับค่า v มาเพื่อหาค่าเป็นเลข binary -> digital.
+    โดยกำหนดค่าเริ่มต้น
+    p: เป็นจำนวนหลักที่ใช้เป้นจำนวนบวก 4 หลัก
+    n: เป็นจำนวนหลักที่ใช้เป็นจำนวนลบ 3 หลัก
+    sign bit : เป็นหลักแรกเสมอ
+    """
+    sign = -1 if v[0] == 1 else 1
+    return sign*sum([v[i]*2**(p-i) for i in range(1,p+n+1)])
+
+
+def values(v,p=4,n=3):
+    a = [ int(i) for i in v]
+    sign = -1 if a[0] == 1 else 1
+    return sign*sum([a[i]*2**(p-i) for i in range(1,p+n+1)])
+
+#v = [0, 0,0,0,1,1,0,0]
+#print(v)
+#print(value(v))
+#v = [1, 0,1,0,1, 0,1,1]
+#print(v)
+#print(value(v))
+#print(values('10001100',p=4,n=3))

week03/test.py

+from assignment import value
+
+
+print(value([0,0,0,0,1,1,0,0]))
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