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Phuengton Chummuel
numer-60-2
Commits
ab2cc52a
Commit
ab2cc52a
authored
Feb 01, 2018
by
Phuengton Chummuel
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add week03 assignment
parent
32781c3b
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3 changed files
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107 additions
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1 deletion
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-1
Chapter 03 Numerics and Error Analysis-checkpoint.ipynb
...s/Chapter 03 Numerics and Error Analysis-checkpoint.ipynb
+0
-0
Chapter 03 Numerics and Error Analysis.ipynb
week03/Chapter 03 Numerics and Error Analysis.ipynb
+72
-1
assignment.py
week03/assignment.py
+35
-0
No files found.
week03/.ipynb_checkpoints/Chapter 03 Numerics and Error Analysis-checkpoint.ipynb
0 → 100644
View file @
ab2cc52a
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week03/Chapter 03 Numerics and Error Analysis.ipynb
View file @
ab2cc52a
...
@@ -235,6 +235,7 @@
...
@@ -235,6 +235,7 @@
"cell_type": "code",
"cell_type": "code",
"execution_count": 15,
"execution_count": 15,
"metadata": {
"metadata": {
"collapsed": true,
"slideshow": {
"slideshow": {
"slide_type": "skip"
"slide_type": "skip"
}
}
...
@@ -289,6 +290,7 @@
...
@@ -289,6 +290,7 @@
"cell_type": "code",
"cell_type": "code",
"execution_count": 26,
"execution_count": 26,
"metadata": {
"metadata": {
"collapsed": true,
"slideshow": {
"slideshow": {
"slide_type": "skip"
"slide_type": "skip"
}
}
...
@@ -336,6 +338,75 @@
...
@@ -336,6 +338,75 @@
"$0.1 \\times 0.1 = 0.01 \\approx 0.0$ \n"
"$0.1 \\times 0.1 = 0.01 \\approx 0.0$ \n"
]
]
},
},
{
"cell_type": "code",
"execution_count": 28,
"metadata": {},
"outputs": [
{
"data": {
"text/plain": [
"[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]"
]
},
"execution_count": 28,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [
"v = [0 ,0,0,0,1 ,1,0,0]\n",
"\n",
"v = [0 , 0,0,0,0,0,0, 0,0,0,0,0]\n",
"\n",
"sign = -1 if v[0] == 1 else 1\n",
"value = 0\n",
"v_len = len(v)\n",
"\n",
"[ i for i in range(1,8)]\n",
"\n",
"# [ 2 ** (4 - i) for i in range(1,8)]\n",
"# sum([ v[i] * 2 ** (4-i) for i in range(1,8) ])"
]
},
{
"cell_type": "code",
"execution_count": 23,
"metadata": {},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"-2.375\n"
]
}
],
"source": [
"def value(v):\n",
" sign = -1 if v[0] == 1 else 1\n",
" return sign * sum([ v[i] * 2 ** (4-i) for i in range(1,8) ])\n",
"\n",
"v = [1 ,0,0,1,0, 0,1,1]\n",
"\n",
"print(value(v))"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": true
},
"outputs": [],
"source": [
"def value(v , a, b):\n",
" sign = -1 if v[0] == 1 else 1\n",
" \n",
" \n",
"\n"
]
},
{
{
"cell_type": "markdown",
"cell_type": "markdown",
"metadata": {
"metadata": {
...
@@ -472,7 +543,7 @@
...
@@ -472,7 +543,7 @@
"name": "python",
"name": "python",
"nbconvert_exporter": "python",
"nbconvert_exporter": "python",
"pygments_lexer": "ipython3",
"pygments_lexer": "ipython3",
"version": "3.
5.2
"
"version": "3.
6.3
"
}
}
},
},
"nbformat": 4,
"nbformat": 4,
...
...
week03/assignment.py
0 → 100644
View file @
ab2cc52a
def
value
(
v
,
p
=
4
,
n
=
3
):
'''
รับค่า v มาเพื่อหาค่าเป็นเลขฐานสิบ
p เป็นจำนวนหลักที่ใช้เป็นบวก 4 หลัก
n เป็นจำนวนหลักที่ใช้เป็นลบ 3 หลัก
sign bit เป็นหลักแรกเสมอ
'''
tmp
=
[
int
(
i
)
for
i
in
v
]
sign
=
-
1
if
tmp
[
0
]
==
1
else
1
return
sign
*
sum
([
tmp
[
i
]
*
2
**
(
p
-
i
)
for
i
in
range
(
1
,
p
+
n
+
1
)])
v
=
[
0
,
0
,
0
,
0
,
1
,
1
,
0
,
0
]
print
(
v
)
print
(
value
(
v
))
v
=
[
1
,
0
,
1
,
0
,
1
,
0
,
1
,
1
]
print
(
v
)
print
(
value
(
v
))
v
=
[
1
,
0
,
0
,
0
,
0
,
0
,
1
,
1
,
0
,
0
,
0
,
0
]
print
(
v
)
print
(
value
(
v
,
6
,
5
))
v
=
'100000110000'
print
(
v
)
print
(
value
(
v
,
6
,
5
))
v
=
'00001100'
print
(
v
)
print
(
value
(
v
))
v
=
'100000101010000'
print
(
v
)
print
(
value
(
v
,
9
,
5
))
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